Question

The Sum of Three numbers is 123. the second number is 9 less than 2 times the 1st number. the 3rd number is 6 more than 3 times the 1st number. find the 3 numbers.

Answer 1

Let the 1st number be x
Let the 2nd number be y
Let the 3rd number be z
y=(2x)-9
z=(3x)+6
We know x+y+z=123
Now we add up the 3 numbers
[x+(2x-9)+3x+6)=123
6x-3=123
6x=126
x=21
y=33
z=69

Answer 2

Let x=!st number
2x-9=2nd number
3x+6=3rd number

x+(2x-9)+(3x+6)=123
x+2x-9+3x+6=123
6x-3=123
6x=126
x=21 This is the 1st number
2x-9=2(21)-9=33 This is the 2nd number
3x+6=3(21)+6=69 This is the 3rd number