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How to graph this system of equations? x + 2y = –10 3x + y = 12
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find the x and why intercepts, and connect them. To find the X-axis intercept, change the y-value to 0. to find the Y-axis intercept, change the x-value to 0. do that for both lines.
can you show please? (:
\[x+2(0) = -10; \therefore x = -10, thus (-10,0) \] (-10,0) would be a point on that line. \[(0)+2y=-10; y = -10/2; y = -5\] therefore the point (0,-5) would be on the line. connect the two points and you have a line.
do the same fore the other line.
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