Question

sove x^4-7x-8=0 and put in a+bi form

Answer 1

on factor is x+1
x^4-7x-8 / x+1 = x^3 -x^2 + x - 8
- now we need to factor this

Answer 2

applying descartes rule we find there is one real and two complex roots
graphing will give you the real root

Answer 3

i tried using factor theorem on x^3 -x^2 + x - 8
but found no integer roots

Answer 4

the two real roots of original equation are
-1 and 2.2
you can use woframalpha to find the two complex roots