Question

Factor completely over the real numbers
m2(3n + 1)2 − 4m2

Answer 1

m^2 [(3n + 1)^2 - 4]
= m^2 [9n^2 + 6n -3]
= 3m^2 (3n^2 + 2n - 1)
= 3m^2 (3n - 1) (n + 1)