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Hey!! Can someone pls help me answer this. derivative of sin(cos y) - cot (x-3x^2) + 2xy = 0. Thank you.:)
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implicit differentiation:\[(\cos(cosy)x-siny )dy -(\sec^2(x-3x^2)(1-6x))dx+2ydx+2xdy=0\]
Thank you so much. I'll absorb this first. ;)
Is this really the correct answer? I'm confused, since I know that the derivative of cot x should be -csc^2 x, and I can't see that from the answer.
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