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Mathematics 23 Online
OpenStudy (anonymous):

x^3+5x^2-7x-35

jimthompson5910 (jim_thompson5910):

x^3+5x^2-7x-35 (x^3+5x^2)+(-7x-35) x^2(x+5)-7(x+5) (x^2-7)(x+5) So x^3+5x^2-7x-35 factors to (x^2-7)(x+5) In other words, x^3+5x^2-7x-35=(x^2-7)(x+5)

OpenStudy (anonymous):

aah i was one number off lol. thanks

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