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OpenStudy (anonymous):
x^3+5x^2-7x-35
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jimthompson5910 (jim_thompson5910):
x^3+5x^2-7x-35 (x^3+5x^2)+(-7x-35) x^2(x+5)-7(x+5) (x^2-7)(x+5) So x^3+5x^2-7x-35 factors to (x^2-7)(x+5) In other words, x^3+5x^2-7x-35=(x^2-7)(x+5)
OpenStudy (anonymous):
aah i was one number off lol. thanks
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