Question

c^2-2cd-80cd^2= (c+10d)(c-8d)??

Answer 1

you mixed up your signs


should be


c^2-2cd-80cd^2= (c-10d)(c+8d)

Answer 2

wait my signs are wrong

Answer 3

lol yea i just noticed that lol thanks

Answer 4

yep because -10+8 = -2 is what we want not 10+-8 = 2

Answer 5

3x^2-20x-7...(3x+1)(x-7)? im a little confused on this one

Answer 6

i figured it out.

Answer 7

First multiply the first coefficient 3 by the last term -7 to get -21


So we need two numbers that BOTH:

a) multiply to -21

AND

b) add to -20 (the middle coefficient)


It turns out that these two numbers are -21 and 1

Answer 8

oh ok

Answer 9

to check your work, you can FOIL out the factored answer and you should get the original expression back

Answer 10

i thought the 3x^2 would throw me off

Answer 11

it might, but if you step through it carefully, then it won't be so bad