Question

The length of a rectangular garden is 3 yard more than twice its width. the perimeter of the garden is 36yd. what are the width and length of the garden?

Answer 1

If the width is w, what's the length (in terms of w)?

Answer 2

x + x + 2x + 3 + 2x +3 = 36
the 2x's are for the "twice the width" part and the two 3's are for the 3yds more part.

then combine like terms
6x+6 = 36

minus the 6 over
6x = 36-6

6x = 30

then just finish out with algebra
x = 30/6

x = 5yds

Answer 3

since the length is 3 yards more than twice the width then l=3+2x and x is the width.
You then add 2(3+2x)+2(x) since there are two widths and length and set that equal to 36. 6+4x+2x=36.
6x+6=36
6x=30
x=5
plug in your value into the length and width equations (3+2x) and (x) to find length and width