Question

FOIL Method to find product
(2x^2-3)(x4-20

Answer 1

(2x^2-3)(x^4-20)


(2x^2)(x^4)+(2x^2)(-20)+(-3)(x^4)+(-3)(-20)


2x^6-40x^2-3x^4+60


2x^6-3x^4-40x^2+60




So (2x^2-3)(x^4-20)=2x^6-3x^4-40x^2+60