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if p is prime and p|ab, then p|a or p|b prove
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since p|a OR p|b, if p|a then the proof is done, so we assume p doesnt divide a and prove p|b. so p and a are relatively prime, so gcd(p,a)=1, by EEA 1=px+ay, thus b=pbx+aby, since p|pbx by the definistion of division and p|aby, p|b
not sure if that works
i guess it does actually
XD
uw math breakin my balls
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lol
mine as well
are u guys in math 135?
i am ya
which section are you in?
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what u mean?
what time do u go to class?
in the morning
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