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36s-49s^3
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36s-49s^3 s(36-49s^2) s(6^2-(7s)^2) s(6+7s)(6-7s) So 36s-49s^3 completely factors to s(6+7s)(6-7s) In other words, 36s-49s^3 = s(6+7s)(6-7s)
grrrr it wouldnt let me type my answer i had to refresh like 5 times
lol I hate that about this site
ok i have a^3+27 (a+9)(a^2+3)
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am i missing something in the middle?
by the sum of cubes formula a^3+27 a^3+3^3 (a+3)(a^2-3a+3^2) (a+3)(a^2-3a+9) So a^3+27 factors to (a+3)(a^2-3a+9)
yup i was
you have the right form, just missing some stuff
yea i had a feeling i was missing a number in the middle
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