If the simple interest on a sum of 2 years at 10%p.a is Rs.1000 and the same amount is borrowed for 2 years at 8%p.a and compounded annually, then find the compound interest and theamout to be paid after 2 years.
a typing mistake = theamout should be the amount
on a sum of 2 years????
P * T * R S.I. = -------- 100 P * 2 * 10 1000 = --------- 100 1000 * 100 ---------- = P 20 so P = 5000 Now put this P in the formula for compound interest and calculate. If u need help, let me know...
do i need to find the amount after the principle
Use this formula for calculating amount [ R ]^n A = P [1 + ---- ] [ 100 ] where n = no. of years then C.I = A - P
i did the answer in this way, is it correct P * T * R S.I. = -------- 100 P * 2 * 10 1000 = --------- 100 1000 * 100 ---------- = P 20 P = 5000 A = 1000 + 5000 = 6000 According to the sum ow A becomes P P = Rs.6000 [ R ]^n A = P [1 + ---- ] [ 100 ] THEN A came as Rs.6,998.4 AND CI = 6,998.4 - 6000 = Rs.19948.4 Is it correct
"ow" moeans "now"
no this is wrong first we find the P using the S.I. formula i.e. P = Rs. 5000 the question says "the same amount" which means the same P is borrowed on C.I. so we have to use the same P i.e. Rs. 5000 in the formula for C.I.
THANKS FOR THE HELP
u r welcome........☺
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