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Find the area of the trapezoid shown. 39√3 sq. units 43.5 sq. units 43.5√3 sq. units
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Area of the trapezoid is \[ \frac{1}{2} \times \text{Sum of the parallel sides } \times \text{Height}\] It is easy to see that the sum of the parallel sides is 10+16+3=29 units,and byusing the properties of right angle triangle we would get height \[ 3\sqrt{3} \space \space \text {units }\],so substituting in the area formula we will get 43.5√3 sq. units
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