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Mathematics 12 Online
OpenStudy (anonymous):

Factor completely p^4 – 2p^2 + 1

OpenStudy (anonymous):

\[(p^2 -1)^2\]

OpenStudy (anonymous):

\[(p-1)(p+1)(p-1)(p+1)\]

OpenStudy (anonymous):

(p – 1)(p + 1)(p2 + 1) (p – 1)^2(p + 1)^2 (p^2 – 1)^2 (p – 1)(p + 1)(p^2 – 1) Those are the choices

OpenStudy (anonymous):

Ok yeah it is (p^2 - 1) ^2

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