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(0.09y^2-0.0016)
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lol
Delta = 0.000576
difference of two squares.
yea but when i work it out it tells me its wrong
answer is \[(0.3y-.04)(0.3y+.04)\]\
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i have (0.03y+0.04)(0.03y-0.04)
am i putting to many zeros?
squares are confusing with decimals
\[0.3^2=0.3\times 0.3=0.09\]
shawna i have no idea what your answer is
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so your answer was off by a decimal for the first term
so should it be (.03y+.04)(.03y-.04)
no it should be \[(.3y+.04)(.3y-.04)\]
oh i see now. what in the world was the answer shawna gave? lol
think that was to some other question
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