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Mathematics 19 Online
OpenStudy (anonymous):

How do you integrate (x/1+x)

OpenStudy (anonymous):

write it as 1 - 1 / (x+1) INT = x + ln|x+1| + c

OpenStudy (anonymous):

correction x - ln|x+1| + c

OpenStudy (anonymous):

I don't understand - is this a rule that you just have to know?

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