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Solve for x. x^2/3=9
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x= 3(sqrt(3))
can i assume you have \[x^{2/3}=9\]
I don't think he means that.
If so raise both sides to the 3/2 power\[\left( x^{2/3} \right)^{3/2}=9^{3/2}\]\[x=\left( 9^{1/2} \right)^3\]
\[x=\left( \sqrt{9} \right)^3=3^3=27\]
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! :) thank you
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