Question

Find an equation for the line passing through the point (6, 1) and perpendicular to the line y=2x-14

Answer 1

1 = -.5(6) + b
1 = -3 + b
4 = b
y = -1/2x + 4

Answer 2

use pt slope rule and use negative reciprocal
y-y1=m(x-x1)
that will give you the equation of your line and to get a perpendicular slope just use the negative reciprocal

Answer 3

so
y-1=-1/2(x-6)
y-1=-1/2x+3
y=-1/2x+4