Question

Which equation is an identity?

a. 4m-4=5m+5-m

b. 14-(4v+7)=-4v - 7

c. 5y+3=5y-3

d. 5w+6-w=6w-2(w-3)

Answer 1

option d

Answer 2

all of em

Answer 3

seems like they all end up with the variable disappearing!

Answer 4

d.

Answer 5

a.4m-4=5m+5-m
4m-5m+m=5+4
0m=9
b.14-4v-7=-4v-7
-4v+4v=-7-14+7
0v=-14
c.5y+3=5y-3
5y-5y=-3-3
0y=-6
d.5w+6-w=6w-2w+6
5w-w-6w+2w=6-6
0w=0
All of the equations are unsolvable because division by 0 is undefined. Why pick on d. as the bad boy? Is it because the left and right is identical in the beginning?