Mathematics
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OpenStudy (anonymous):
solve for θ in the following equation:Sin 2θ=cosθ
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OpenStudy (anonymous):
^^
OpenStudy (jamesj):
I'll help you quickly this:
OpenStudy (anonymous):
no3 question haha thank u
OpenStudy (jamesj):
You should have a formula for sin(2.theta)
\[\sin(2\theta) = 2 \sin \theta . \cos \theta\]
OpenStudy (jamesj):
Hence if sin(2.theta) = cos(theta), that implies .... what? Simplify the expression.
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OpenStudy (anonymous):
u said before 1 right?
OpenStudy (jamesj):
?
OpenStudy (anonymous):
w8
OpenStudy (anonymous):
if i simply it with my poor brain i think they are the same?
OpenStudy (jamesj):
Sin 2θ=cosθ
=> 2 sin θ . cosθ = cosθ
=> 2 sin θ = 1
=> sin θ = 1/2
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OpenStudy (jamesj):
Now you just have to say for what values of θ is sin θ = 1/2
OpenStudy (anonymous):
1/2
OpenStudy (jamesj):
What is sin(30) and sin(60)?
OpenStudy (anonymous):
sin(30)
OpenStudy (jamesj):
(You should learn by heart the sin, cos and tan all these angles
0, 30, 45, 60, 90.)
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OpenStudy (jamesj):
What is the value of sin(30 degrees)?
OpenStudy (anonymous):
1/2
OpenStudy (jamesj):
right. Now are there other θ for which sin θ = 1/2. Yes. So you need to write them all down.
OpenStudy (anonymous):
ok