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OpenStudy (anonymous):
A 0.500-kg particle has a speed of 2.40 m/s at point A and kinetic energy of 7.60 J at point B. -What is the net work done on the particle by external forces as it moves from A to B?
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OpenStudy (anonymous):
=(
OpenStudy (anonymous):
1/2 (.5 (2.4^2))=1.44 net work =change in k.e so 7.6-1.44=6.16J
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