Question

How would i check this in my calculator if it is correct or not.

log(8) x + log(8) (x+30) = 2
log(8) (2x+30) = 2
8^2 = 2x+30
64 = 2x+30
34 = 2x
17 = x

If i wanted to plug it back in.

Answer 1

wrong!!... log add means times...

Answer 2

log(8)x + log(8)(x+30)=2
log(8)[x(x+30)]=2
x(x+30)=8^2
x^2+30x=64
x^2+30x-64=0
(x+32)(x-2)=0
x+32=0 or x-2=0
x=-32 or x=2
(rejected)

(in log x must be positive number...)
so x=2

Answer 3

sorry i hv a network problem

Answer 4

u can try.. use your calculator and try
1. log(-any number)(+any number)
2. 1og(+any number)(-any number)

Answer 5

u will see that cant use...

Answer 6

Thanks!

Answer 7

welcome

Answer 8

^^