Question

solve 3x^2-1=5x

Answer 1

Move over the 5x to the other side of the equation by subtracting it from both sides: \[3x ^{2}-5x-1=0\] and then factor. It is a quadratic equation. So find two numbers that multiply to (a*c) or (3*-1) and add to (b) or (-5)

Answer 2

\[3x^2 -1= 5x => 3x^2-5x-1=0 => \]
Delta = 25+12= 37

x = \[\frac{5\pm \sqrt{37} }{6}\]

Since thirtyseven is no perfect square, those two are your solutions.