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A game board has 8 cards, and 2 say WIN. Mike picks up 2 cards without replacing the first. What is the probability neither say WIN?
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\[\frac{^6C_2\ ^2C_0}{^8C_2}\]
6/8 for the first one and 5/7 for the second so the probability neither say win is (6*5)/(8*7)
a certain sense of deja vu
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