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Solve by Factoring. x^3-5x^2-4x+20=0
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\[x= [5,2,-2]\]
x2(x-5)-4(x-5)=(x2 -4)(x-5)=0 x2 -4=0 x2 =4 x_1,_2= +/- 2 x-5=0 x_3=5 - so those solutions are -2,2,5
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