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Mathematics 22 Online
OpenStudy (anonymous):

Hi everyone! is there someone some can help me to answer right the mathe assignment that i will put on an attachments. Thanks a lot! Assignment 3

OpenStudy (anonymous):

OpenStudy (anonymous):

i have answered many question, but iam not sure, please help me to win this assignment.

OpenStudy (kira_yamato):

D for qn 18

OpenStudy (anonymous):

you have to find it's speed : 2(3+v) + 5v = 32 6 + 7v = 32 7v = 26 v = 3 5/7

OpenStudy (anonymous):

Can you help me please with all the questions?

OpenStudy (anonymous):

I will be watting for your answers...please. do not let me alone.

OpenStudy (anonymous):

Yes i am waitting for...

OpenStudy (anonymous):

It is important for me to win this assignment. Please guys help me!

OpenStudy (anonymous):

Ruby what is the time limit?

OpenStudy (anonymous):

Who knows the answer now? i can waite...

OpenStudy (anonymous):

I will try solving your assignment in I hour I am mean after 1 hour

OpenStudy (anonymous):

You will have to wait, a little

OpenStudy (anonymous):

ok i will ...I will be here waitting for your answers.

OpenStudy (anonymous):

for Q1 ans is C) 1.2 for Q2 ans is B) for Q3 ans is B)

OpenStudy (anonymous):

ok, you are an angel. I keep waitting for the rest.

OpenStudy (anonymous):

I'll answer as many as I can.....

OpenStudy (anonymous):

ok please keep helping me!

OpenStudy (anonymous):

6.D

OpenStudy (anonymous):

Q5 ans is A) Q7 ans is D) Q8 I am not very familiar with the notations used but since it is x^2 it will give positive result for both negative and positive values because (7)^2 = 49 and also (-7)^2 = 49 so choose yr notation accordingly

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

@Ishaan 94 what is the meaning of w with bar ? is it additive inverse of w ???

OpenStudy (anonymous):

i do not know

OpenStudy (anonymous):

I think some of your answers are wrong.

OpenStudy (anonymous):

like Q18, you put C, but I am very sure the correct answer is D

OpenStudy (anonymous):

Conjugate@harkirat

OpenStudy (anonymous):

ok, thanks Ishaan....

OpenStudy (anonymous):

Also Q4 , you said there is no solution , but I am fairlyh sure there is.

OpenStudy (anonymous):

what are right and wrong?

OpenStudy (anonymous):

also, Q20, think you have to recheck that.

OpenStudy (anonymous):

Q4,18,20 I am fairly sure those are wrong.

OpenStudy (anonymous):

20 is c

OpenStudy (anonymous):

iok what are the right answers then>?

OpenStudy (anonymous):

4 is right i think

OpenStudy (anonymous):

4 is not correct.

OpenStudy (anonymous):

correct answer of 4 is B.

OpenStudy (anonymous):

no 2/5 is not a sol

OpenStudy (anonymous):

equations where you have one absolute value equal to another must pretty much always have atleast one solution. Just by geometry.

OpenStudy (anonymous):

Q13 ans should be E) Q14 and Q15 are correct..

OpenStudy (anonymous):

1 not 2

OpenStudy (anonymous):

they have given 2 only sol is -5/4

OpenStudy (anonymous):

huh, probably, I was too lazy to actually solve it because it is so late , so I went to wolframa: http://www.wolframalpha.com/input/?i=%7C9x%2B3%7C+%3D%7Cx-7%7C

OpenStudy (anonymous):

16 shud be d

OpenStudy (anonymous):

But there is no reason why the solution is null set.

OpenStudy (anonymous):

all hail wolfram

OpenStudy (anonymous):

even if it is so of, "the most correct".

OpenStudy (anonymous):

oh.. didnt see that sign |

OpenStudy (anonymous):

ur right

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Q17 ans is D)

OpenStudy (anonymous):

Now u hv many peepl helping u and I hv to run.. so best of luck....☺

OpenStudy (anonymous):

14 is right

OpenStudy (anonymous):

i am confussed now. one says diferent answer to others.

OpenStudy (anonymous):

What are the right answers then for all.

OpenStudy (phi):

I have to say that half of your answers were wrong. It surely is an affront to the universe for you to turn in a perfect paper when you have no idea what is going on.

OpenStudy (anonymous):

can you help me to fix it.

OpenStudy (anonymous):

what am i going to do>? who will help me....

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