Question

Find the differential dy. Please explain
1/(x+1)

Answer 1

\[y=\frac{1}{x+1}\]We just find the ordinary derivative:\[dy/dx=\frac{0-1}{(x+1)^2}\]\[dy=\frac{-1}{(x+1)^2}dx\]

Answer 2

I used the quotient rule above, then separated dy and dx