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Mathematics 17 Online
OpenStudy (anonymous):

Evaluate m^0 - n^2 for m = 2 and n = -1.

OpenStudy (pottersheep):

Anything to the power of 0 = 1

OpenStudy (pottersheep):

m^0 - n^2 2 ^ 0 - (-1)^2 1 - 1 0

OpenStudy (anonymous):

thanks guysss :)

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