Question

Let f(x)=x^2+1 and h(x)=sqrt(2x) . Find a formula for f(h(x))=

Answer 1

consider sqrt(2x) as your x in f(x), so f(h(x)) should be f(sqrt(2x))=sqrt(2x)^2+1=2x+1

Answer 2

\[f(h(x)) = [\sqrt{2x}]^2 + 1 = 2x +1\]

Answer 3

Yours is better.