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Mathematics 8 Online
OpenStudy (anonymous):

int_{1}^{9} (1/sqrt{x}) dx I need to find the average value. Can anyone help with this please?

OpenStudy (anonymous):

\[\int\limits_{1}^{9} (1/\sqrt{x}) dx\]

OpenStudy (anonymous):

I had my integral of sqrt of x wrong. I got the correct answer. The correct answer is 1/2 in case anyone else needs this too.

OpenStudy (turingtest):

do you still need help then?

OpenStudy (anonymous):

No, thanks!!

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