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hat is square root 300 minus square root 3
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\[\sqrt{300}= \sqrt{3*10*10} = 10\sqrt{3}\]
so \[\sqrt{300} - \sqrt{3} = 10\sqrt{3} - \sqrt{3} = 9\sqrt{3}\]
is that the final answer
yes it is.....
unless u want it in decimal.........
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no
that's it ,thanks
What is \[\sqrt{108}\] + \[2\sqrt{3}\] - \[\sqrt{75}\]
root(108) = root(2*2*3*3*3) = 2*3root(3) = 6 root(3) root(75) = root(3*5*5) = 5 root(3)
thank you
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so \[\sqrt{108} + 2\sqrt{3} - \sqrt{75} = 6\sqrt{3} + 2\sqrt{3} - 5\sqrt{3} = 3\sqrt{3}\]
one more question. \[\sqrt{125}-\sqrt{245}-\sqrt{45}\]
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