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prove: [(3x+2)/x-1]-6/5=0
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prove?
solve.. yes..
please?
is it \[\frac{3x+2}{x-1}-\frac{6}{5}=0\] or \[\frac{3x+2}{x}-1-\frac{6}{5}=0\]
the first one..
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\[\frac{3x+2}{x-1}-\frac{6}{5}=0\] \[\frac{3x+2}{x-1}=\frac{6}{5}\] \[3x+2=\frac{6}{5}(x-1)\] multiply through by 5 \[15x+10=6(x-1)\] \[15x+10=6x-6)\] \[9x=-16\] \[x=-\frac{16}{9}\]
thank you so much
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