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Factor the polyomial completely using any method 3n^3-10n^2-48n+160 Medal given if answered
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3n(n2-16)-10(n2-16)=(3n-10)(n2-16)
n^2(3n-10)-16(3n-10) (3n-10)(n^2-16) (3n-10)(n+4)(n-4)
yes n2-16=(n-4)(n+4)
jhonyy9, that's not completely
thanks guys , medal gievn
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n=4 is a factor, so we will use synthetic division from here:
I mean a zero
Synthetic Division? For this? Not necessary
(n-4)(3n^2+2n-40)...
(n+4)(n-4)(3n-10) is the answer
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Man I'm lagging, I couldn't see any of your answers when I posted :/
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