Question

Determine the number of x intercepts.

f(x) = -X^2+6x+3

Answer 1

Using Descartes' Rules of Signs:
1 positive real root
1 negative real root

two real roots, two x-intercepts

Answer 2

x_1,_2=(-6+/-sqrt(36+12))/-2=(-6+/- 4sqrt3)/-2= 3+/-2sqrt3

Answer 3

the discriminate is \[6^2-4(-1)(3)>0\]so there must be two x-ints (since the equation has two real roots)

Answer 4

Thank you!

Answer 5

np :})