Question

Factor the polyomial completely using any method 6a^4+13a^2-5
Medal given for answer

Answer 1

let x = a^2
6a^4+13a^2-5

substituting:

6x^2 + 13x - 5
(6x + 3)(6x + 10 )/6
3(2x + 1)2(3x + 5)/6
(2x + 1)(3x + 5)

substituting back:
(2a^2 + 1)(2a^2 + 5)

Ans. (2a^2 + 1)(2a^2 + 5)

Answer 2

Thanks :) medal given

Answer 3

sorry, small problem, correcting...

Answer 4

let x = a^2
6a^4+13a^2-5

substituting:

6x^2 + 13x - 5
(6x - 2)(6x + 15 )/6
2(3x - 1)3(2x + 5)/6
(3x - 1)(2x + 5)

substituting back:
(3a^2 - 1)(2a^2 + 5)
( sqrt(3)a - 1)(sqrt(3)a + 1)(2a^2 + 5)

Ans. ( sqrt(3)*a - 1)(sqrt(3)*a + 1)(2a^2 + 5)