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OpenStudy (anonymous):

Factor the polyomial completely using any method 2ac^2-5bc^2-2ad^2+5bd^2 Medal given for answer

OpenStudy (anonymous):

\[2ac^2-5bc^2-2ad^2+5bd^2\]factor GCF from first two and second two terms\[=c^2(2a-5b)-d^2(2a-5b)\]factor out the binomial as a GCF\[=(2a-5b)(c^2-d^2)\]the second binomial is a difference of two squares\[=(c-d)(c+d)(2a-5b)\]is the factored form

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