Why would the vertical asymptotes be at pi/2 and -3pi/2? The horizontal shift is -pi/4... but instead they're shifting it over -pi/2, why

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jamesj · Answer

What's the function or functions you're talking about?

anonymous · Answer

attachment

jamesj · Answer

lol.  My crystal ball is getting re-polished, so I had to ask.

anonymous · Answer

I know sorry it was an old question I had typed in that OpenStudy once again did not manage to post... I gotta find it just hold on a minute while I ask a question relating to the problem I'm currently working on... just didn't want to lose this one.

anonymous · Answer

Okay visual here