Question

find the exact value of:
arctan(-square root of 3)
answer in radians in terms of pi

Answer 1

well .... cos(pi/6) = 1/2 and sin(pi/6) = sqrt(3)/ 2
=> tan(pi/6) = sqrt(3)

and
tan(-pi/6) = -sqrt(3)

because sin(-pi/6) = - sqrt(3)/2 and cos(-pi/6) = 1/2

Answer 2

look at unit circle on last page of cheat sheet. if a point on the circle where the ratio of the second coordinate to the first is
\[-\sqrt{3}\] and then make sure to answer with an angle (number) in the interval
\[[-\frac{\pi}{2},\frac{\pi}{2}]\] in other words on the right half of the circle