Question

Find the value of sin θ from a right triangle with base of 9ft, vertical side 12 ft, and theta is the angle next to the right angle.
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/ | 12 ft
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9 ft the base angle to the left of the nine is theta.

Answer 1

\[\tan \theta = \frac{12}{9} = \frac{4}{3} \]
\[ h = \sqrt{4^2 + 3^2}\times 3 = 15\times3\]
\[\sin\theta = \frac{12}{15}= \frac{4}{5}\]

Answer 2

and the cotangent?

Answer 3

\[\cot\theta = \frac{1}{\tan \theta} = \frac{3}{4}\]
have a nice day :)

Answer 4

sorry, again, i meant cosine lol

Answer 5

\[\cos \theta = \frac{9}{15} = \frac{3}{5}\]