Question

The line tangent to the curve y = 4 − x^2
at the point (2, 0) also passes
through the point (0, a). Find a. Is a = 0?

Answer 1

slope of the tangent = y' = -2x
at (2,0) this slope = -4
equation of tangent is

y-0 = -4(x-2)
y = -4x + 8

when x = 0 y = 8
a = 8

Answer 2

Thank you!