Question

PLEASEe help. Write an equation in the form ax^2 + bc + c for quadratic function that passes thru (8,0) (0,8)(-2,0

Answer 1

pelasepleaseplease

Answer 2

the axis of symmetry is exactly between the 2 roots
The distance between -2 and 8 on the x-axis is 10. mid way is x=3

Use this form of the parabola:
y= a(x-3)^2+h

You have 3 points, so you can solve for a and h. Once you have them, multiply out to get the equation into the form
y= ax^2 +bx +c