Question

estimate a safe speed x for a stopping distance of 276 feet.

1/2x^2+11/3x=276

Answer 1

y = (1/2)x^2 + (11/3) x < 276

Trying various values of x:

at x = 18, y = 228
at x = 20, y = 273 1/3
at x = 21, y = 297 1/2

So a safe speed could be 20 ft/sec assuming the constants (1/2) and (11/3) are in secs