In 1995, life expectancy of males in a certain country was 68.9 years. In 2000, it was 72.8 years. Let E represent the life expectancy in year t represent the number of years since 1995.
The linear function E(t) that fits the data is
E(t)=?t+?
(rounded to the nearest tenth)
Use the function to predict life expectancy of males in 2008?
E(13)=?
(rounded to the nearest tenth)
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OpenStudy (saifoo.khan):
C'mon!! :/
OpenStudy (anonymous):
i think E(t)=68.9t+72.8
OpenStudy (saifoo.khan):
You are correct.
OpenStudy (anonymous):
but the thing i get stuck on is the rounding to the nearest tenth
OpenStudy (anonymous):
so that should read like so
70t+73
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OpenStudy (saifoo.khan):
The best part it, i hate this problem.. speically it's rounding off part. LOL.
OpenStudy (anonymous):
yes but this one had me stuck but the part with the nearest tenth not so bad
OpenStudy (anonymous):
what do you think does that look good
OpenStudy (saifoo.khan):
No, when i got it wrong, it gave me a similar answer.
OpenStudy (saifoo.khan):
you can skip this.. do this one in the end.
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