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Physics 19 Online
OpenStudy (anonymous):

We have two electric charges, Q1 and Q2 located in a vacuum. If we change the gap by material relative permittivity equal to 4, what happens to the force exerted these charges? Justify answer with the calculations. (a) The force exerted mutually multiplied by 2. (b) The force exerted mutually divided by 4 · E0. (c) The force exerted mutually divided by 4. (d) The force exerted mutually multiplied by E0.

OpenStudy (anonymous):

I think that the correct is c. By coulomb. Im right??

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