Question

What are the solutions to\[x^2 =-1\]

Answer 1

x = sqrt(-1)
x = +i, -i

Answer 2

x = ±i

Answer 3

\[x^2=-1\]\[\sqrt{x^2}=\sqrt{-1}\]\[x= i\] Note that it is NOT plus minus... i is defined as -1^(1/2) to get -i you have to do something like: \[-\sqrt{-1}\]

Answer 4

but (-i)^2 = -1

so -i is a solution

Answer 5

along with plain i