Question

Completely factor the expression
48x²y + 72xy² + 27y³

Answer 1

\[48y \cdot x^2+72y^2 \cdot x +27y^3\]
this is in the form of
\[Ax^2+Bx+C\]
where
A=48y
B=72y^2
C=27y^3
we want to find two factors of A*C that have product A*C and have sum
B.
A*C=48y * 27y^3=48(27)y^4=24(54)y^4=12(108)y^4=36(36)y^4
=36y(36y)

Answer 2

so B=36y^2+36y^2
so Bx=36xy^2+36xy^2

Answer 3

i made a mistake om A*C
A*C=36y^2(36y^2)

Answer 4

\[48y \cdot x^2+36xy^2+36xy^2+27y^3\]
i wil leave the factor by grouping to you