Question

factor the sum and differences of cubes. 8/27 + m^6

Answer 1

I am not sure of what you want but this is the factorization of your expression:

\[ \frac{8}{27} + m^6 = \frac{1}{27} \left(3 m^2+2\right) \left(9 m^4 -6 m^2+4\right) \]

Answer 2

this is great ty again

Answer 3

Glad to help :)