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Mathematics 9 Online
OpenStudy (anonymous):

solve absolute value of |(3x+1)/(x-1)| < 2

OpenStudy (anonymous):

\[|(3(x+2/3 -5/3 +5/3))/(x-1)|<2\]pulled out 3 then +'s and -'s 5/3 \[|(3(x-1 +5/3))/(x-1)|<2\] \[|3(x-1)/(x-1) +3(5/3)/(x-1)|<2\] \[|3 +5/(x-1)|<2\] \[-2<3 +5/(x-1)<2\] \[-5<5/(x-1)<-1\] \[-1/5>(x-1)/5>-1 \] \[-1>x-1>-5 \] \[0>x>-4 \] |dw:1318926816965:dw|

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