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8x * 1/4y
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2x/y
\[8x \times 1\div4y\]
What is the question? Do you need to simplify? Than 2x/y
\[DS: Rate = 3+c Time = 9/3+c D=9 | tapos| US: Rate=3-c, Time =3/3-c. D=3\]
no the working for 8x×1÷4y
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The working?
Oh, wrong question
yes andras
I dont know what you need to do, sorry.
\[8x*1/4 y\] \[= \frac{8x*1}{4y}\] \[= \frac{8x}{4y}\] \[= \frac{2x}{y}\] is that a bit more clear?
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yes
\[= 8x \div1 \times 1\div4y\] \[=32xy \times 1 \div4y\] \[8x\]
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