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Exponential to Logarithmic form
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9 ^1/2 =3
the form b^y=x becomes log_{b}_(x)=y
Sorry, computer hella laggy...
if y = 10 ^x then x = log to base 10 of y
also, 9^(1/2) = sqrt(9) any number to the power (1/2) is the same as square root of the number
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I need to change 9^(1/2) =3 into Logarithmic form, so would it be \[\log_9{3}= 1/2 \]
yup
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